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Six cards numbered with the digits 3,4,5,6,7,8 are shuffled and laid in a row to make a five-digit number.
What is the probability that this number is divisible by 9?
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3 + 4 + 5 + 6 + 7 + 8 = 33.
a) 33 - 3 = 30
b) 33 - 4 = 29
c) 33 - 5 = 28
d) 33 - 6 = 27
e) 33 - 7 = 26
f) 33 - 8 = 25.
So, we have 6 cases (6 sums), and we see that among the sums of any 5 cards, only one is divisible by 9 :
it is case d), where the sum is 27.
Therefore, the probability under the question is .
Solved and answered.