SOLUTION: Tickets were sold for R200 and R300 a total of 250 tickets were sold. The total amount taken for the show was R 55 000. Determine how many of each tickets were sold

Algebra ->  Percentage-and-ratio-word-problems -> SOLUTION: Tickets were sold for R200 and R300 a total of 250 tickets were sold. The total amount taken for the show was R 55 000. Determine how many of each tickets were sold      Log On


   



Question 1138094: Tickets were sold for R200 and R300 a total of 250 tickets were sold. The total amount taken for the show was R 55 000. Determine how many of each tickets were sold
Answer by ikleyn(52781) About Me  (Show Source):
You can put this solution on YOUR website!
Solution

Let x = # of the  R300 tickets, y = # of  R250  tickets.


From the condition, you have these 2 equations


         x +      y =   250       (1)    (counting tickets)

     300*x +  200*y = 55000       (2)    (counting money)


From equation (1), express  y = 250 - x  and substitute it into equation (2). You will get


      300*x + 200*(250-x) = 55000.


Express x and calculate answer


    x = %2855000+-+200%2A250%29%2F%28300+-+200%29 = 50.


Then from equation (1),  y = 250 - 50 = 200.


ANSWER.  50  R300 tickets and 200 R200 tickets.


CHECK.   50*300 + 200*200 = R55000.   ! Correct !

The problem solved using 2-equation setup and the Substitution method.

--------------

It is a standard and typical ticket problem.

For ticket problems,  read the lessons
    - Using systems of equations to solve problems on tickets
    - Three methods for solving standard (typical) problems on tickets
in this site.

From these lessons,  learn on how to solve such problems once and for all.

Also,  you have this free of charge online textbook in ALGEBRA-I in this site
    - ALGEBRA-I - YOUR ONLINE TEXTBOOK.

The referred lessons are the part of this online textbook under the topic "Systems of two linear equations in two unknowns".