SOLUTION: At a wedding, 4/9 of the audience were female and the rest male. 1/3 of the adults were female. if there were 85 male children. How many attended the wedding altogether

Question 1134157: At a wedding, 4/9 of the audience were female and the rest male. 1/3 of the adults were female. if there were 85 male children. How many attended the wedding altogether
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
let t = total people attending wedding
let a = number of adults
let g = no. of little girls
85 = no. of little boys
At a wedding, 4/9 of the audience were female and the rest male.
t female; t male
1/3 of the adults were female.
then
of the adult are males
:
I don't think there is enough information here to do this, but we can make some reality assumptions.
All solutions have to be integers, the number of girls has to be at least 85, (more little girls at a wedding seems reasonable)
And the total no. has to number divisible by 9, to accommodate these fractions
:
total males - adult male = 85 boys
t - a = 85
total females - adult females = g
t a = 85
:
Multiply the female equation by 2, subtract the male equation
t a = 2g
t a = 85
--------------------------------- subtraction eliminates a
t = 2g - 85
rewrite this equation to
2g = t + 85
g =
Put this equation y= in my Ti83, looking at the table
the first integer solution where g>85 and t is divisible by 9
t = 279 and g = 89
Check this by finding the number of adults
279-(89+85) = 185, we are not able to divide this into 3rds evenly so this is not our solution:
:
The next is t = 297 and g = 92
Find the number of adults: 297-(92+85) = 120, divisible be 3 (80 males, 40 females)
I am going to say we have a total of 297 people,
consisting of
80 male adults
40 female adults
85 boys
92 girls
--------
297 people

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