SOLUTION: A father distributes R1500 to his children, Jane, Karen and Eddie, in the ration J:K:E, respectively. If Jane gets twice as much as Karen, who in turn gets three times as much as

Question 1132486: A father distributes R1500 to his children, Jane, Karen and Eddie, in the ration J:K:E, respectively. If Jane gets twice as much as Karen, who in turn gets three times as much as Eddie, how much does each child receive?
Answer by ikleyn(52790) (Show Source): You can put this solution on YOUR website!
.

Let x be the amount received by Eddie.


Then Karen received 3x, while Jane received 2*(3x) = 6x.


The total is


    x + 3x + 6x = 1500.


    10x = 1500  ====>  x =  = 150.


Answer.  Eddie received  R150;  Karen received  3*R150 = R450;  Jane received  2*R450 = R900.


CHECK.   150 + 450 + 900 = 1500.    ! Correct !

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Regarding your formulation, you can omit this part "in the ration J:K:E, respectively" totally.

It does not carry any info and is excessive.

A true Math problem formulation should not contain excessive parts, words, etc.

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