SOLUTION: A photograph measuring 8 cm by 6 cm is reduced with a constant ratio so that the length of the photograph is 2 cm. Find the ratio of the areas of the new to the old photographs.

Algebra.Com
Question 1126663: A photograph measuring 8 cm by 6 cm is reduced with a constant ratio so that the length of the photograph is 2 cm. Find the ratio of the areas of the new to the old photographs.
Answer by solver91311(24713)   (Show Source): You can put this solution on YOUR website!


Presuming that you are using the standard and commonly accepted meaning of the term "length", then you have reduced the 8 cm dimension to 2 cm, a factor of one-fourth. If you reduce the other dimension by the same ratio, then since the area is calculated by multiplying the length times the width the ratio of the areas would be the product of the reduction ratios of the two dimensions. In other words, one-fourth times one-fourth.


John

My calculator said it, I believe it, that settles it


RELATED QUESTIONS

a photograph measuring 7 1/2 cm by 5 cm is enlarged so that the larger side is 24 cm.... (answered by LinnW)
a photograph measuring 7.6 cm wide and 12.7 cm long is enlarged so that its width is 30.4 (answered by josmiceli)
Solving Problems with Quadratic Equations 22. A photograph measures 21 cm by 15 cm. A... (answered by arallie)
A rectangular photograph is twice as long as it is wide. The perimeter of the photograph (answered by algebrahouse.com)
a photograph measures 21cm by 15 cm. A strip of constant width is to be cut from each... (answered by josgarithmetic)
steve's photograph is thrice as long as it is wide. It mounted so that a border 2cm... (answered by josgarithmetic)
A length of the photograph is 7 cm longer than the width. Its area is 30 cm^2. Find the... (answered by JBarnum)
A photograph measures 20 cm by 16 cm. A strip of constant width is to be cut off the top... (answered by drk)
The height of a photograph is 40 cm greater than the width, and the area of the... (answered by jorel555)