SOLUTION: Direct Variations:
The amount of electric current required to melt a fuse wire varies as the three-halves power of the diameter. if the current required to melt a wire of diamet
Algebra.Com
Question 1104356: Direct Variations:
The amount of electric current required to melt a fuse wire varies as the three-halves power of the diameter. if the current required to melt a wire of diameter 0.02 inch is 15 amperes, what current will be required to melt a wire of the same material having a diameter of 0.08 inch?
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
The amount of electric current required to melt a fuse wire varies as the three-halves power of the diameter.
if the current required to melt a wire of diameter 0.02 inch is 15 amperes, what current will be required to melt a wire of the same material having a diameter of 0.08 inch?
:
let a = current when diameter is .08"
A direct variation equation
=
cross multiply
a =
Calc
.002828a = .022627*15
a =
a = 120 amps to blow a .08" fuse wire
RELATED QUESTIONS
When an electric current flows through a wire, the resistance to flow varies directly as... (answered by greenestamps)
A transformer can change
alternating current to direct current.
the voltage of an... (answered by Alan3354)
Direct Variations:
If y varies directly as the cube of x, and y=32 when x=2, find y=5. (answered by josgarithmetic)
Translate each statement into a mathematical statement. Use k as the constant of... (answered by Cromlix)
Ohm’s law states that the amount of current that flows through a wire varies inversely as (answered by Boreal)
1.The number of hours h required for a block of ice to melt varies inversely with the... (answered by josgarithmetic)
Express the following as an equation in which k represents the constant of... (answered by ikleyn)
The electric power P varies jointly as the resistance R and the square of the current I.... (answered by Theo)
Electricity. The power P in an electric circuit varies directly with the square of the... (answered by Alan3354)