Let P be the weight of the plastic pail alone and let W be the weight of water when it is fills the pail.


Then the first part of the condition gives you this equation:

P = 0.2*(P+W).        (1)


Let R be the weight of the remaining amount of water.
Then the second part of the condition gives you another equation 

P + R = 0.6*(P+W).    (2)


From (1), you have  

P = 0.2P + 0.2W  ====>  0.8P  = 0.2W  ====>  P =  = .     (3)


From (2), you have 

P + R = 0.6*(P+W) = 3*0.2*(P+V) = 3P  ====>  R = 3P - P = 2P  ====>  substitute P =  from (3)  ====>  

R =  =  = 0.5W.


Hence, the weight of the remaining water R is 0.5W.


In other words, the percent of water remained in the pail is 50%.