.
Let D be the length of the track.
(As you will see from the solution, the value of D does not participate in the solution;
so it does not matter even in which linear units we measure D).
Then the speed of the faster track is linear units per second,
while the speed of the slower track is linear units per second.
The condition that the faster car will pass/overtake the slower is that the faster car will travel the distance
exactly D units longer than the slower track, or
- = D.
After canceling the factor D in both sides this equation takes the form
- = 1.
Simplify and solve for "t". First step is to multiply both sides by 75:
5t - 3t = 75 ====> 2t = 75 ====> t = = 37.5 seconds.
Answer. The faster car will pass/overtake the smaller car in 37.5 seconds.
Solved.
There is the lesson
- Problems on bodies moving on a circle
in this site, where similar problem is solved and presented (Problem 2).
Also, you have this free of charge online textbook in ALGEBRA-I in this site
ALGEBRA-I - YOUR ONLINE TEXTBOOK.
The referred lesson is the part of this textbook under the section "Word problems", the topic "Travel and Distance problems",
where you will find many other advanced and non-traditional Travel and Distance problems.
Save the link to this online textbook together with its description
Free of charge online textbook in ALGEBRA-I
https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson
to your archive and use it when it is needed.
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Today I solved 16 problems for you and got back 0 (zero, ZERO) "thanks" from you.
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