SOLUTION: Find three consecutive numbers such that three times the first number is equal to the sum of the other two

Question 1059111: Find three consecutive numbers such that three times the first number is equal to the sum of the other two
Answer by solve_for_x(190) (Show Source): You can put this solution on YOUR website!
Let x represent the first of the three numbers.

The next two consecutive numbers (assumed to be integers) are x + 1 and x + 2.

Since "three times the first number is equal to the sum of the other two", you can write:

3x = (x + 1) + (x + 2)

3x = 2x + 3

3x - 2x = 3

x = 3

The three numbers are then:

x = 3

x + 1 = 3 + 1 = 4

x + 2 = 3 + 2 = 5

Solution: The numbers are 3, 4, and 5.
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