SOLUTION: The time T necessary to make an enlargement of a photo of negative varies directly as the area A of the enlargement. If 180 seconds are required to make a 5-by-7 enlargement, find

Algebra.Com
Question 1054438: The time T necessary to make an enlargement of a photo of negative varies directly as the area A of the enlargement. If 180 seconds are required to make a 5-by-7 enlargement, find the time required for 6-by-6 enlargement.
Answer by Boreal(15235)   (Show Source): You can put this solution on YOUR website!
180 seconds=k*35 (the square inches in 5*7)
k=180/35
x seconds=k*36=(180/35)*36
x=185.14 seconds.

RELATED QUESTIONS

The time necessary T to make an enlargement of a photo negative varies directly as the... (answered by rapaljer)
The time T necessary to make an enlargement of a photo negative varies directly as the... (answered by rfer)
The time T necessary to make an enlargement of a photo negative varies directly as the... (answered by edjones)
The time needed to make a photo enlargement varies jointly as its length and width. If it (answered by Boreal)
the height of a photo is 4 inches more than its width. After enlargement the height will... (answered by ankor@dixie-net.com)
A photograph that measures 5cm by 12cm is enlarged to a width of 7cm.... (answered by Cromlix)
The rules for a photo contest state that entries must have an area no greater than 100cm2 (answered by addingup)
a rectangular original photo has a lenght of 15cm and 9cm in width. Find the width of the (answered by RoRo Jaxson)
A photo is measured to be 9 inches by 11 inches. A poster enlargement of the photo will... (answered by math_helper)