SOLUTION: Two cars start from towns 570 mi apart and travel toward each other. They meet after 6 hr. Find the speed of each car if one travels 15 mph faster than the other.

Question 1050495: Two cars start from towns 570 mi apart and travel toward each other. They meet after 6 hr. Find the speed of each car if one travels 15 mph faster than the other.
Found 2 solutions by stanbon, josmiceli:
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Two cars start from towns 570 mi apart and travel toward each other. They meet after 6 hr. Find the speed of each car if one travels 15 mph faster than the other.
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slower car rate:: x mph
faster car rate:: x+15 mph
combined speed:: 2x+15 mph
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Equation:
rate = distance/time
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2x+15 = 570/6
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2x + 15 = 95
2x = 80
x = 40 mph
x+15 = 55 mph
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Cheers,
Stan H.
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Answer by josmiceli(19441) (Show Source): You can put this solution on YOUR website!
Let = the speed of the slower car in mi/hr
= the speed of the faster car in mi/hr
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Think of this as one car standing still and the other
car moving at the sum of their speeds
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and

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The faster car's speed is 55 mi/hr
The slower car's speed is 40 mi/hr
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check answers:

mi
and

mi
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mi
OK
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