SOLUTION: A chef is using a mixture of two brands of Italian dressing. The first brand contains 6% vinegar, and the second brand contains 11% vinegar. The chef wants to make 210 milliliters

Question 1035164: A chef is using a mixture of two brands of Italian dressing. The first brand contains 6% vinegar, and the second brand contains 11% vinegar. The chef wants to make 210 milliliters of a dressing that is 8% vinegar. How much of each brand should she use?
Found 2 solutions by ikleyn, jorel555:
Answer by ikleyn(52800) (Show Source): You can put this solution on YOUR website!
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A chef is using a mixture of two brands of Italian dressing. The first brand contains 6% vinegar, and the second brand
contains 11% vinegar. The chef wants to make 210 milliliters of a dressing that is 8% vinegar. How much of each brand should she use?
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x + y = 210, (1) 0.06*x + 0.11*y = 0.08*210, (2) Multiply (1) by 100 and simplify. You will get the modified system x + y = 210, (1') 6*x + 11*y = 1680. (2') Solve it by using the Substitution method. From (1') express x = 210 - y and substitute into (2'). You will get a single equation 6*(210-y) + 11y = 1680, 1260 - 6y + 11y = 1680, 5y = 1680-1260, 5y = 420, y = = 84. Answer. 84 milliliters of the 11% vinegar and 210-84 = 126 milliliters of the 6% vinegar. Check. 0.06*126 + 0.11*84 = 16.80. Correct!

Answer by jorel555(1290) (Show Source): You can put this solution on YOUR website!
Let n be the amount of 6% mixture:
.06(n)+.11(210-n)=.08(210)
.06n+23.1-.11n=16.8
.05n=6.3
n=6.3/.05=126ml of .06 mixture, and 84 ml of .11 mixture needed!!!!!!!!!
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