SOLUTION: Factorise fully 6k+12k^2-3k^3
Algebra.Com
Question 1010885: Factorise fully 6k+12k^2-3k^3
Answer by fractalier(6550) (Show Source): You can put this solution on YOUR website!
6k + 12k^2 - 3k^3 =
3k(2 + 4k - k^2) = -3k(k^2 - 4k - 2)
RELATED QUESTIONS
Factorise fully... (answered by fractalier)
Factorise fully... (answered by fractalier)
3k 3k^3 - 7k^2
_________ x ___________
3k^2 - 7k 3k^3 -... (answered by jim_thompson5910)
parallel circuit
find total resistor
R1 = 12k
R2 = 6K
R3 = 3K
(answered by london maths tutor)
48-6k=-12k (answered by jim_thompson5910)
Factorise fully... (answered by fractalier)
Factorise fully... (answered by Edwin McCravy)
Factorise fully... (answered by addingup)
factorise fully:... (answered by DrBeeee)