SOLUTION: I need some help on how to solve a mixture solving problem.
How many gallons of 65% antifreeze and how many gallons of 20% antifreeze should be mixed to obtain 50 gallons of a
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Question 100993: I need some help on how to solve a mixture solving problem.
How many gallons of 65% antifreeze and how many gallons of 20% antifreeze should be mixed to obtain 50 gallons of a 56% mixture of antifreeze?
Thank you!
Answer by scott8148(6628) (Show Source): You can put this solution on YOUR website!
x(65%)+(50-x)(20%)=50(56%) ... .65x+10-.2x=28 ... .45x=18 ... x=40
40 gal of 65% ... 10 gal of 20%
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