SOLUTION: Jack wants to mix a 70% acid solution with 20% acid solution to get 80 L of 50% solution how much does he need Each solution
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Question 1009396: Jack wants to mix a 70% acid solution with 20% acid solution to get 80 L of 50% solution how much does he need Each solution
Answer by norymae(15) (Show Source): You can put this solution on YOUR website!
let x= 70% selution
80-x=20% solution
.7(x)+.2(80-x)=.5(80)
.7x+16-.2x=40
.7x-.2x=40-16
.5x=24
.5x÷.5=24÷.5
x=48
80-x=80-48=32
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