SOLUTION: If Cynna won 80% of the games and had played 16 winning games, how many total games had she played?
Algebra.Com
Question 1007100: If Cynna won 80% of the games and had played 16 winning games, how many total games had she played?
Answer by Theo(13342) (Show Source): You can put this solution on YOUR website!
x represents the number of games she played.
80% is equivalent to the fraction of 80/100 = .8
.8 * x = 16
divide both sides of this equation by .8 to get:
x = 16/.8
solve for x to get x = 20.
20 games were played in total.
she won 80% of them.
80% of 20 is equal to .8 * 20 which is equal to 16.
RELATED QUESTIONS
The Blue Skies won 17 more games than they lost. They played 52 games in all and had 3... (answered by TimothyLamb)
The team’s ratio of games won to games played was 3 to 8. If the team played 56 games,... (answered by Alan3354)
Sue played the same computer game.
She won 12 of the games she played, and so she... (answered by nerdybill)
A softball team won 84% of the games they played last season. If they played 25 games,... (answered by stanbon)
the lions won 15% of all the games they played. They won 9 games? how many games did they (answered by richwmiller)
The ratio of the number of games Elly won to the number of games she lost is 7/3. she... (answered by stanbon)
Valley High School's football team played a total of 16 games. They won twice as many... (answered by Tatiana_Stebko)
The sweat hogs lost four times as many games as they won. IF they played 80 games, how... (answered by ben720)
The Sweat Hogs lost four times as many games as they won. If they played 80 games, how... (answered by tommyt3rd)