SOLUTION: how many milileters of a 20% acis solution must be mixed with 30ml of an 80% acid solution to make a 32% acid solution? i have to show a chart and fill it out

Question 100006: how many milileters of a 20% acis solution must be mixed with 30ml of an 80% acid solution to make a 32% acid solution? i have to show a chart and fill it out
Answer by Nate(3500) (Show Source): You can put this solution on YOUR website!
[80%(30) + 20%(x)]/[30 + x] = 32%
[0.8(30) + 0.2x]/[30 + x] = 0.32
[24 + 0.2x]/[30 + x] = 0.32
24 + 0.2x = 0.32[30 + x]
24 + 0.2x = 9.6 + 0.32x
14.4 = 0.12x
120 = x
Maybe implement different values for your chart. Use different situations to find the solution. 120mL of 20%
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