Questions on Word Problems: Problems on percentages, ratios, and fractions answered by real tutors!

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Question 150567This question is from textbook
: there were 3/4 as many women as there men in a train yesterday. at the next station, 12 women and 6 men got in. as a result, there were 6/7 as many women as men on the train. how many men and women were in the train at first?This question is from textbook
: there were 3/4 as many women as there men in a train yesterday. at the next station, 12 women and 6 men got in. as a result, there were 6/7 as many women as men on the train. how many men and women were in the train at first?
Answer by josmiceli(2035) About Me  (Show Source):
You can put this solution on YOUR website!
Initially,
(1) w = (3/4)*m
(2) w + 12 = (6/7)*(m + 6)
Substitute (1) in (2)
(3/4)m + 12 = (6/7)*m + 36/7
Multiply both sides by 28
21m + 12*28 = 24m + 4*36
21m + 336 = 24m + 144
3m = 192
m = 64
And, since
w = (3/4)*m
w = (3/4)*64
w = 48
At first, there were 64 men and 48 women