SOLUTION: Find the point D(x,y) such that the points A(-3,1), B(4,0), C(0,-3) and D are the corners of a square. Justify your answer.
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Distance formul
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Question 773915: Find the point D(x,y) such that the points A(-3,1), B(4,0), C(0,-3) and D are the corners of a square. Justify your answer.
****** Start of solution: ******
Distance formula:
So side AC of the square:
= sqrt( (0 - (-3))^2 + (-3-1)^2 )
= sqrt( 9 + 16 )
= 5
I don't know how to continue. . .
Answer by josgarithmetic(39617) (Show Source): You can put this solution on YOUR website!
This can be done without using Distance Formula, since the four points are vertices of a square. (You CAN use the distance formula if you want.)
Segment AD // segment CB
Line AD has slope
Using point A(-3,1) and slope 3/4 in point-slope form equation,
Line AD______
Segment BD // segment CA
Line BD has slope, since is perpendicular to line AD, of .
Using point B(4,0) and slope -(4/3) in point-slope form equation,
Line BD_____
Point D(?,?) is the intersection of the two lines, and .
------remaining process would be solve the system.
------easiest way would be clear the fractions and use the equations in standard form..
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