SOLUTION: OK, so my home work is on Algebra 1
My problem is about "GEOMETRY: PARALLEL
and PERPENDICULAR LINES.
Write the slope-intercept form of an equation for the line that passes throu
Algebra.Com
Question 704258: OK, so my home work is on Algebra 1
My problem is about "GEOMETRY: PARALLEL
and PERPENDICULAR LINES.
Write the slope-intercept form of an equation for the line that passes through the given point and is PARALLEL to the graph of each equation.
(2,3) Y=X+5
PLease help
Found 2 solutions by lynnlo, KMST:
Answer by lynnlo(4176) (Show Source): You can put this solution on YOUR website!
y=x+1
Answer by KMST(5328) (Show Source): You can put this solution on YOUR website!
Parallel lines have the same slope,
because slope is the change in y for an x increase of 1,
and that is the tangent of the angle the line makes with the positive x axis.
is the equation of a line in form.
That is the unique and very useful form that starts with "y=".
The number added at the end (5 in this case) is the intercept,
the y value for x=0, and therefore the y- coordinate of the point where the line "intercepts" the y-axis.
The number multiplying the x (an invisible 1 in this case) is the slope.
You can see that for x=0, y=5, but if you increase x by one,
for x=1, y=1+5 has increased by 1.
The line parallel to will have and an intercept, to be determined.
Its equation will be
We know that for that line the
point with has so substituting into we get
--> -->
and the equation is
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