SOLUTION: the parallel sides of a trapezium are a and b respectively. find the value of a + b if it has a area of 20cm2 and the distance between the parallel sides is 5cm. 1/2(a+b)(5)=20

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Question 642256: the parallel sides of a trapezium are a and b respectively. find the value of a + b if it has a area of 20cm2 and the distance between the parallel sides is 5cm.
1/2(a+b)(5)=20
i do not understand the next step
a+b=20 x 2 + 5

Answer by Edwin McCravy(20056)   (Show Source): You can put this solution on YOUR website!
(a+b)(5) = 20

Multiply both sides by (2) to clear of fractions:

(2)(a+b)(5) = (2)20

The (2) and the  multiply to give 1 and (2) times the 20 
multiply to give 40.  So we now have

(1)(a+b)(5) = 40

We can remove the (1)

   (a+b)(5) = 40

Next we divide both sides by 5:

   = 

Now we can cancel the (5) and the 5, and 40 divided by 5 gives 8.
So we have:

   = 8

  (a+b) = 8

Edwin





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