SOLUTION: construct a paralellogram ABCD in which BC=5.5cm, CD=2.5cm and angle ABC=60 degrees. Measure AC and BD

Question 57824: construct a paralellogram ABCD in which BC=5.5cm, CD=2.5cm and angle ABC=60 degrees. Measure AC and BD
Answer by venugopalramana(3286) (Show Source): You can put this solution on YOUR website!
construct a paralellogram ABCD in which BC=5.5cm, CD=2.5cm and angle ABC=60 degrees. Measure AC and BD
IN A PARALELOGRAM OPPOSITE SIDES ARE EQUAL.
HENCE AB=CD=2.5....BC=DA=5.5
DRAW BC = 5.5.
WITH B AS CENTRE DRAW AN ARC OF RADIUS = AB = 2.5.
AT B DRAW A LINE BX MAKING ANGLE OF 60 DEGREES WITH BC..THAT IS ANGLE XBC=60
LET THE ARC CUT BX AT A.
WITH A AS CENTRE AND RADIUS EQUAL TO AD=5.5 DRAW AN ARC.
WITH C AS CENTRE AND RADIUS EQUAL TO CD=2.5 DRAW AN ARC.
LET THE 2 ARCS CUT AT D.
JOIN CD AND DA
ABCD IS THE REQUIRED PARALLELOGRAM.
AC^2=AB^2+BC^2-2*AB*BC*COS(60) = 22.75
AC=4.77=4.8
BD=AC^2+CB^2-2*AC*CB*COS(120)= 50.25
BD=7.09=7.1

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