SOLUTION: Determine the vertex of y=x^2-8x+22

Question 56886This question is from textbook
: Determine the vertex of y=x^2-8x+22 This question is from textbook

Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
Determine the vertex of y = x^2 - 8x + 22
:
Use the vertex equation: x = -b/(2a)
:
This is based on the form: ax^2 + bx + c
:
In your equation a = 1, b = -8, c = 22 (not used here)
:
x = -(-8)/(2*1)
x = +8/2
x = 4 is where the vertex line passes thru and is the x value for the max or the min of the equation. When a is positive it will be min, and when a is negative it will be a max.
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