SOLUTION: How do I prove that DEFG is a parallelogram? When Quadrilateral DEFG has vertices d(a,b) E(a+c,b)F(a+c+d,b+e)G(a+d,b+e).

Question 54418: How do I prove that DEFG is a parallelogram? When Quadrilateral DEFG has vertices d(a,b) E(a+c,b)F(a+c+d,b+e)G(a+d,b+e).
Answer by venugopalramana(3286) (Show Source): You can put this solution on YOUR website!
How do I prove that DEFG is a parallelogram? When Quadrilateral DEFG has vertices d(a,b) E(a+c,b)F(a+c+d,b+e)G(a+d,b+e).
MID POINT OF DF = [{(A+A+C+D)/2},{(B+B+E)/2}]=[(2A+C+D)/2 , (2B+E)/2 ]
MID POINT OF EG = [{A+C+A+D}/2 , {B+B+E}/2] = [(2A+C+D)/2 , (2B+E)/2 ]
THAT IS MID POINTS ARE SAME...THAT IS DIAGONALS BISECT EACH OTHER...HENCE IT IS A PARALLELOGRAM
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