SOLUTION: Find the equation of the line passing though (0, 4) and parallel to the line 3x+5y+15=0

Question 516273: Find the equation of the line passing though (0, 4) and parallel to the line 3x+5y+15=0
Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
3 x + 5 y = -15
Find the slope of this line
make y the subject

5 y = -3 x + -15
Divide by 5
y = -0.6 x -3
Compare this equation with y=mx+b
slope m = -0.6
The slope of a line parallel to the above line will be the same
The slope of the required line will be -0.6
m= -0.6 ,point ( 0 , 4 )
Find b by plugging the values of m & the point in
y=mx+b
4 = 0.00 + b
b= 4
m= -0.6
Plug value of the slope and b in y = mx +b
The required equation is y = -0.6 x + 4
(y = - 3/ 5 x + 4)
m.ananth@hotmail.ca

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