SOLUTION: the width of a rectangle is 12 units less than the length. the perimeter is 108 units. find the length.

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Question 389441: the width of a rectangle is 12 units less than the length. the perimeter is 108 units. find the length.

Found 2 solutions by ewatrrr, gwendolyn:
Answer by ewatrrr(24785)   (Show Source): You can put this solution on YOUR website!

Hi,
Let x and (x-12)represent the length and width respectively

Question states***
2x + 2(x-12) = 108
solving for x
4x - 24 = 108
4x = 132
x = 33 units, the length
CHECKING our Answer***
66 + 2*21 = 66 + 42 = 108
Answer by gwendolyn(128)   (Show Source): You can put this solution on YOUR website!
Let W be the width of the rectangle and L be the length.
We know that the width is 12 units less than the length, so:
W = L - 12
We also know the perimeter is 108 units, so:
2*W + 2*L = 108
Substitute the value for w from the first equation:
2*(L - 12) + 2L = 108
Distribute the 2 on the right and combine the L terms:
2L - 24 + 2L = 108
4L - 24 = 108
Add 24 to both sides:
4L -24 + 24 = 108 + 24
4L = 132
Divide both sides by 4:
L = 33
So, the length is 33 units.

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