Hi

a)probability that an 18-year-old man selected at random is between 68 and 70 inches tall

 

 = .5  NORMSDIST(.5)  = .6915

= -.5  NORMSDIST(-.5) = .3085

P(-.5 < z > .5) = .6915 - .3085 = .3829  Or 39.29%



b)random sample of sixteen 18-year-old men is selected

test statistic = 

 z= 1/(2/4)  =  2  NORMSDIST(2)  = .6915 = .9773

 z = -1/(2/4)= -2  NORMSDIST(-2)  = .6915 = .0228

P(-2 < z > 2) = .9973 - .0228 = .9545  Or 95.45%

 

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