SOLUTION: It asks: The perimeter of parallelogram JKLM is 52cm, and JK is 2cm longer than JM.
Find JK and find JM
(JK is x+2 in length and JM is x in length)
I have tried To solve this
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Question 347661: It asks: The perimeter of parallelogram JKLM is 52cm, and JK is 2cm longer than JM.
Find JK and find JM
(JK is x+2 in length and JM is x in length)
I have tried To solve this problem and I can't seem to figure it out.I am doing something wrong.Please help!
Answer by Earlsdon(6294) (Show Source): You can put this solution on YOUR website!
You are given the perimeter (P) of the parallelogram:
P = 52
The perimeter of any quadrilateral (of which a parallelogram is an example) is found by adding the lengths of the four sides of the figure.
The lengths are:
x, x, x+2, and x+2, so let's add these up and set the sum equal to the given perimeter of P = 52.
x+x+(x+2)+(x+2) = 52 Simplify the right side by adding the x's together.
4x+4 = 52 Subtract 4 from each side.
4x = 48 Finally, divide both sides by 4.
x = 12 and x+2 = 14.
So, JK = 12cm, and JM = 14cm.
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