SOLUTION: The vertices of parallelogram ABCD are A(0,0), B(7,0), C(12,8), and D(5,8). Find, to the nearest degree, the measure of angle DAB.
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Question 308242: The vertices of parallelogram ABCD are A(0,0), B(7,0), C(12,8), and D(5,8). Find, to the nearest degree, the measure of angle DAB.
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
The vertices of parallelogram ABCD are A(0,0), B(7,0), C(12,8), and D(5,8). Find, to the nearest degree, the measure of angle DAB.
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AB is on the x-axis.
tan(DAB) = 8/5
DAB = 58º
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