SOLUTION: find the value of each variable. 3a-5, b+3, 2a, 2b-1

Algebra.Com
Question 268700: find the value of each variable. 3a-5, b+3, 2a, 2b-1
Answer by persian52(161)   (Show Source): You can put this solution on YOUR website!
3a-5_a=2a

First find the solution to the equation.
a=2a

Move all terms not containing a to the right-hand side of the equation.
-a=0

Multiply -a by -1 to get a.
a=0*-1

Solve the equation before evaluating.
a=0

Now that values have been found for each variable, the expression can be evaluated.
3a-5_a=0

Replace the variable a with 0 in the expression.
3(0)-5

Multiply 3 by each term inside the parentheses.
0-5

Combine all similar expressions.
Answer: -5
*¨**¨**¨**¨**¨**¨**¨**¨**¨**¨**¨**¨**¨**¨**¨*
b+3_b=2b-1

First find the solution to the equation.
b=2b-1

Move all terms not containing b to the right-hand side of the equation.
-b=-1

Multiply -b by -1 to get b.
b=-1*-1

Solve the equation before evaluating.
b=1

Now that values have been found for each variable, the expression can be evaluated.
b+3_b=1

Replace the variable b with 1 in the expression.
(1)+3

Remove the parentheses around the expression 1.
1+3

Add 3 to 1 to get 4.
Answer: 4

RELATED QUESTIONS

Given that {{{(3a+4b)/(2a-2b) =5, }}} find the value of... (answered by ikleyn)
if 2a+3b=9and 3a+2b=16 find the value of... (answered by mananth)
3a - 2b =21 a + 3b = -4 what is the value of each variable (a and... (answered by MathLover1)
HELP NEEDED! :) If 3a+4b/2a-2b=5 Find the value of... (answered by macston)
2a + b =7 3a - 2b... (answered by josgarithmetic)
use the elimination method to solve the system. 2a+b=3... (answered by Alan3354)
How would I use the elimination method? 2a+b=3... (answered by MathLover1)
FIND THE VALUE OF 'X' BY QUADRATIC FORMULA 1. 9x^2-9(a+b)x+2a^2+5ab+2ab^2=0... (answered by jim_thompson5910)
This question is on the Addition Method rather than the Substitution Method. When using... (answered by Abbey,guapa)