SOLUTION: find the surface area of a square pyramid with a base of 2 yds and a slant ht of 2 yds.

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Each triangle has area = (1/2)*base*height
triangle area = (1/2)*2*2
triangle area = 2 yds^2

There are 4 triangles, so their combined area is 8 yds^2

Base is a square, whose area is 2*2 --> 4yds^2

To total SA = 12yds^2

jon.