SOLUTION: find the surface area of a square pyramid with a base of 2 yds and a slant ht of 2 yds.
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Question 25605: find the surface area of a square pyramid with a base of 2 yds and a slant ht of 2 yds.
Answer by longjonsilver(2297) (Show Source): You can put this solution on YOUR website!
Each triangle has area = (1/2)*base*height
triangle area = (1/2)*2*2
triangle area = 2 yds^2
There are 4 triangles, so their combined area is 8 yds^2
Base is a square, whose area is 2*2 --> 4yds^2
To total SA = 12yds^2
jon.
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