SOLUTION: Two opposite angles of a parallelogram have measures 3x-20 and 2(x+5) respectively. Find the measures of the angles
Two consecutive angles of a parallelogram have measures 4(x+5)
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Question 208683: Two opposite angles of a parallelogram have measures 3x-20 and 2(x+5) respectively. Find the measures of the angles
Two consecutive angles of a parallelogram have measures 4(x+5) and 2(3x+20) respectively. Find the measures of the angles.
Two consecutive angles of a parallelogram have measures 2(x+12) and 2(5x+6) respectively. Find the measures of the angles.
Answer by RAY100(1637) (Show Source): You can put this solution on YOUR website!
Remember opposite angles of a parallelogram are congruent(equal)
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and,,,if parallel lines cut by transversal,,same side interior angles are supplementary,,,,,,or consecutive angles of a parallelogram are supplemental
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a),,,3x-20 = 2(x+5) =2x+10
x=30
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Angles are 70 degrees
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check,,,3(30)-20=70=2(30+5),,,,,ok
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b),,,4(x+5) + 2(3x+20) =180
4x +20 +6x +40 =180
10x = 120
x=12
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Angles are,,68,,,112
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4(12+5)=68,,,,2(3*12+20)=112,,,68+112=180,,,,ok
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c),,,2(x+12) + 2(5x+6) = 180
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2x +24 +10x +12 = 180
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12x = 180-36=144
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x=12.
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angles are,,48,,,,132
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check ,,,48 +132 =180,,,ok
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