SOLUTION: Could someone help? - The vertices of a parallelogram are A(-4,-1),B(5,-6), C(11,-3) and D(2,2). Show that the diagonals bisect each other.

Question 175534: Could someone help?
- The vertices of a parallelogram are A(-4,-1),B(5,-6), C(11,-3) and D(2,2). Show that the diagonals bisect each other.
Answer by nycsub_teacher(90) (Show Source): You can put this solution on YOUR website!
The vertices of a parallelogram are A(-4,-1),B(5,-6), C(11,-3) and D(2,2). Show that the diagonals bisect each other.
A parallelogram is a quadrilateral with both pairs of opposite sides parallel.
A parallelogram has:
A- 2 sets of parallel sides
B- 2 sets of congruent sides
C- opposite angles congruent
D- consecutive angles supplementary
E- diagonals bisect each other
F- diagonals form 2 congruent triangles
Plot all 4 points on the coordinate plane (I would use graph paper).
Then connect each point to form your parallelogram.
Find the distance from point A to point C and then the distance from point B to point D using the distance formula for points.
If the distances are equal, then the diagonals bisect each other.
Can you take it from here?

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