There are three solutions. The first is (-4,-1), because it must 
be as far to the left of and as far below (-2,2) as (1,-1) is of
(3,2).



The second is (6,-1), because it must be as far to the right 
of and as far below (3,2) as (1,-1) is of (-2,2).



The third is (0,5), because it must be 
1. as far right of (-2,2) as (-1,1) is left (3,2)
and
2. as far above (-2,2) as (1,-1) is below (3,2).



Edwin