SOLUTION: Please help me solve this problem The sides AB and AD of a square are extended 10cm and 6cm,respectively,to form sides AE and AF of a rectangle. At most how long is the side of th

Question 152270This question is from textbook Algebra and Trigononmetry
: Please help me solve this problem
The sides AB and AD of a square are extended 10cm and 6cm,respectively,to form sides AE and AF of a rectangle. At most how long is the side of the square if the perimeter of the rectangle is at least twice the perimeter of the square? This question is from textbook Algebra and Trigononmetry

Answer by checkley77(12844) (Show Source): You can put this solution on YOUR website!
2*THE ORIGINAL SQUARE PERIMETER IS THE PERIMETER OF THE 10 cm & 6 cm EXTENDED SIDES OF THE SQUARE TO FORM A RECTANGLE.
2*4X=2(X+10)+2(X+6)
8X=2X+20+2X+12
8X-4X=32
4X=32
X=32/4
X=8 FOR THE ORIGINAL SIDES OF THE SQUARE (AB & AD)
PROOF:
2*4*8=2(8+10)+2(8+6)
64=2*18+2*14
64=36+28
64=64

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