SOLUTION: The base angles of a trapezoid are 34˚ and 48˚, respectively. If its upper and lower bases are 120m and 220m, respectively, compute the area of the trapezoid. (Hint: Get the h of

Algebra ->  Parallelograms -> SOLUTION: The base angles of a trapezoid are 34˚ and 48˚, respectively. If its upper and lower bases are 120m and 220m, respectively, compute the area of the trapezoid. (Hint: Get the h of      Log On


   



Question 1185145: The base angles of a trapezoid are 34˚ and 48˚, respectively. If its upper and lower bases are 120m and 220m, respectively, compute the area of the trapezoid. (Hint: Get the h of the trapezoid by using the triangles on the side of the trapezoid).
Answer by josgarithmetic(39621) About Me  (Show Source):
You can put this solution on YOUR website!
If the two triangle ends (both as right-triangles) could be shuved together to get rid of the rectangular part, then there are

Left right triangle: leg x and y, angle opposite of y is 34 degree; angle opposite of x is 56 degree.
Right right triangle: leg 100-x and y, angle opposite of y is 48 degree, and angle opposite of 100-x is 42 degree.

The two triangles together form a segment of 220-120=100 meters; split into x and 100-x.

To find what is y, the HEIGHT of the original trapezoid:
system%28y%2Fx=tan%2834%29%2Cy%2F%28100-x%29=tan%2848%29%29-------------use this system to solve for y.
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y=%28100%2Atan%2834%29%2Atan%2848%29%29%2F%28tan%2834%29%2Btan%2848%29%29
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highlight_green%28y=41.96452%29

and then,...
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