I won't do your for you. I'll do one exactly like it.ABCD is rhombus. If ∠BAC = 36°, find ∠ADB and ∠ABC.
∠DAC = 36° because the diagonals of a rhombus bisect each other. AC ⊥ BC because the diagonals of a rhombus are perpendicular. ΔAED is a right triangle because two sides are perpendicular. ∠ADB = 54° because the two angles of a right triangle are complementary. AB ≅ AD Sides of a rhombus are congruent ΔABD is isosceles 2 sides congruent ∠ABD = 54° Base angles of isosceles triangle are congruent AB ≅ BC Sides of a rhombus are congruent ΔABC is isosceles 2 sides congruent ∠BCA = 36° Base angles of isosceles triangle are congruent ∠BAC + ∠BCA + ∠ABC = 180° Property of all triangles ∠ABC = 180° - ∠BAC - ∠BCA ∠ABC = 180° - 36° - 36° = 108° Now do yours the same way. Edwin