SOLUTION: Parallelogram ABCD; AC bisects with BD at E; AE= 3x + y, EC= 2x + y, find values of x and y

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Question 1133434: Parallelogram ABCD; AC bisects with BD at E; AE= 3x + y, EC= 2x + y, find values of x and y
Found 2 solutions by ikleyn, Alan3354:
Answer by ikleyn(52782)   (Show Source): You can put this solution on YOUR website!
.
In each parallelogram, the diagonals bisect each other.


Therefore, from the given condition, you have


    |AE| = |EC|,   or   3x + y = 2x + y,


which implies


    3x = 2x,   and then   x = 0.


ANSWER.  x= 0.   y can be any number (it can not be defined by an unique way from the given data).

Solved, answered and completed.


Answer by Alan3354(69443)   (Show Source): You can put this solution on YOUR website!
Parallelogram ABCD; AC bisects with BD at E; AE= 3x + y, EC= 2x + y, find values of x and y
--------------
The lengths of AE and EC are equal.
3x + y = 2x + y
3x = 2x
x = 0
y is not defined.
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