SOLUTION: 1. Rearrange the following formula to make y the subject of the equation. a. b. c. d=7y−4 k=−3y+5+6y t=−8(y−1)2 2. 3t − 6 = − 2t + 6 Sol

Algebra ->  Parallelograms -> SOLUTION: 1. Rearrange the following formula to make y the subject of the equation. a. b. c. d=7y−4 k=−3y+5+6y t=−8(y−1)2 2. 3t − 6 = − 2t + 6 Sol      Log On


   

Question 1125864: 1. Rearrange the following formula to make y the subject of the equation.
a. b. c.
d=7y−4 k=−3y+5+6y
t=−8(y−1)2
2.
3t − 6 = − 2t + 6
Solve for t.
Prove your solution is correct.
3. The area A of a circle is given by the equation: A= π r2
where π is a constant approximately equal to 22 and r is the radius of the circle. 7
What is the radius of a circle if it has an area of 616 cm2?
4. Find the gradient and the intercept of the following two lines:
a. y=2x+4
b. 2y–2x=4
c. Are these two lines parallel? Justify your answer.
a. Expand the following 3x(y − x2 − 2x)
a. b.
b. Factorise the following expression: 4a3b + 6ab2
Answer by MathLover1(20855) About Me  (Show Source):
You can put this solution on YOUR website!
1. Rearrange the following formula to make y the subject of the equation.
a.
d=7y-4
d%2B4=7y
y=%28d%2B4%29%2F7
b.
k=-3y%2B5%2B6y
k=5%2B3y
k-5=3y
y=%28k-5%29%2F3
c.
t=-8%28y-1%29%5E2
t%2F%28-8%29=%28y-1%29%5E2
-t%2F8=%28y-1%29%5E2
-sqrt%28t%2F8%29=sqrt%28%28y-1%29%5E2%29
-sqrt%28t%29%2Fsqrt%282%5E2%2A2%29=y-1
-sqrt%28t%29%2F2sqrt%282%29=y-1
y=1-sqrt%28t%29%2F2sqrt%282%29
y=1-%28sqrt%28t%29sqrt%282%29%29%2F%282sqrt%282%29sqrt%282%29%29
y=1-%28sqrt%28t%29sqrt%282%29%29%2F%282%2A2%29
y=1-%28sqrt%28t%29sqrt%282%29%29%2F4

2.
3t+-6+=+-2t+%2B+6
Solve for+t.
3t+%2B2t+=+6+%2B+6
5t+=+12
t+=+12%2F5
Prove your solution is correct.
3t+-6+=+-2t+%2B+6....substitute t
3%2812%2F5%29+-6+=+-2%2812%2F5%29+%2B+6
36%2F5+-%286%2A5%29%2F5+=+-24%2F5+%2B+%286%2A5%29%2F5
36%2F5+-30%2F5+=+-24%2F5+%2B+30%2F5
6%2F5+=6%2F5

3.
The area A of a circle is given by the equation:
A=+pi%2A+r%5E2 where pi is a constant approximately equal to 3.14 and r+is the radius of the circle.
What is the radius of a circle if it has an area of 616cm%5E2?
616cm%5E2=+pi%2A+r%5E2
616cm%5E2%2F3.14=+r%5E2
r=sqrt%28616cm%5E2%2F3.14%29
r=14.01cm


4.
Find the gradient and the intercept of the following two lines:
first arrange the line’s equation into slope-intercept form which is y+=+mx+%2B+b
If y is alone on the left side, then m is the slope of line, and b will just be the y-intercept of that line
a.
y=2x%2B4... already in slope-intercept form
so, m=2 and y-intercept b=4
b.
2y-2x=4
2y=2x%2B4
y=2x%2F2%2B4%2F2
y=x%2B2
so, m=1 and y-intercept b=2
c. Are these two lines parallel? Justify your answer.
these lines are not parallel because parallel lines have same slopes
as we can see one line has a slope m=2 and other line m=1
here is the graph:
+graph%28+600%2C+600%2C+-10%2C+10%2C+-10%2C+10%2C+2x%2B4%2C+x%2B2%29+

a. Expand the following 3x%28y+-x%5E2+-+2x%29
3xy+-3x%2Ax%5E2+-+3x%2A2x%29
3xy+-3x%5E3+-+6x%5E2%29
b. Factorize the following expression: 4a3b+%2B+6ab%5E2+
4a%5E3%2Ab+%2B+6ab%5E2=2ab%282a%5E2%2B3b%29+