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Calculate area of a trapezium ABCD with bases 24 cm, 10 cm and sides 13 cm , 15 cm
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Draw the segment from the "upper left" angle of the trapezoid parallel to the other lateral side of the trapezoid
till the intersection with the opposite base.
Then the trapezoid is divided in triangle and parallelogram.
The triangle has the side dimensions of 13, 15 and 24-10 = 14 centimeters.
Calculate the area of the triangle using the Heron's formula
A = ,
where s is semi-perimeter s = = 21. Then
A = = 7*3*4 = 84 cm^2.
Now you can calculate the altitude of the triangle drawn to the base of 14 centimeters.
The altitude h is = = 12 cm.
Next you can determine the area of the parallelogram. It is 10*12 = 120 cm^2.
Finally, the area of the trapezoid is 84 + 120 = 204 cm^2.
Solved.
On the Heron's formula see the lessons
- Proof of the Heron's formula for the area of a triangle
- One more proof of the Heron's formula for the area of a triangle
in this site.
Also, you have this free of charge online textbook on Geometry
GEOMETRY - YOUR ONLINE TEXTBOOK
in this site.
The referred lessons are the part of this online textbook under the topic "Area of triangles".