SOLUTION: In the dia gram, PQ is parallel to AC,given that BQ=4cm,BC=10cm
And area BPQ=8,find
A) area of triangle ABC
B) area of PQC
C) area of triangle AQC
I have a drawing but do
Algebra.Com
Question 1032761: In the dia gram, PQ is parallel to AC,given that BQ=4cm,BC=10cm
And area BPQ=8,find
A) area of triangle ABC
B) area of PQC
C) area of triangle AQC
I have a drawing but do not how to upload or draw??pls help
Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
Area of BPQ =8
BQ = 4
there fore PM altitude =
8= 1/2 *4* PM
PM = 4
The altitude of BPC = PM = 4
Area of triangle BPC = 1/2 * 4* 10
= 20 sq units
Area OF PQC = Area BPC - BPQ = 12 sq units
Now PQ || AC and AC is common side
triangles AQC & PQC are congruent
Areas are equal 12 sq units
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