Lesson Proof of Opposite sides of a parallelogram are equal

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In this lesson we will prove the basic property of a parallelogram that the opposite sides in a parallelogram are equal. The converse is also true that if opposite sides of a quadrangle are equal then its a parallelogram.

Theorem: If ABCD is a parallelogram then prove that its opposite sides are equal.


drawing( 160, 160, -10, 10, -10, 10, line( -6, -6,4,-6) , line(-6,-6,8,2),line( -6, -6,-2,2), line( -2, 2,8,2) , line( 8, 2,4,-6) ,locate( -6.5,-6.5,A),locate( 4.5,-6.5,B),locate( 8.5,3.5,C),locate(-2.5,4,D))


Proof:
By Parallelogram definition, line AB is parallel to line CD and line BC is parallel to line DA.

We are required to prove that AB = CD and BC = DA.

Let AC be the diagonal of parallelogram.

Consider two Triangles ABC and CDA as shown in figure.

In triangles,

1.  Angle CAB = Angle ACD .....(The line AC is a transversal of parallel lines AB and CD,hence Angle CAB and ACD are alternate angles)

2. Angle ACB = Angle CAD .....(The line AC is a transversal of parallel lines BC and DA,hence Angle ACB and Angle CAD are alternate angles)

3. AC = CA ......(The common side to two triangles)

From conditions 1,2 and 3,

Triangles ABC and CDA are congruent (By Angle -Side-Angle congruency property)

Hence as triangles are congruent triangles , the corresponding sides are equal,

so AB = CD and BC = DA.

QED

To learn more about Similar and congruent triangles you can refer to wikipedia article.

To learn more about parallelogram you can refer to wikipedia

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