# SOLUTION: A rectangle is 10 cm longer than it is wide. A line segment cuts the area enclosed into two pieces, one of which is a square. The area of the rectangle is 118cm squared more than t

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 Click here to see ALL problems on Parallelograms Question 66513: A rectangle is 10 cm longer than it is wide. A line segment cuts the area enclosed into two pieces, one of which is a square. The area of the rectangle is 118cm squared more than the area of the square. What is the width of the rectangle?Answer by ankor@dixie-net.com(16523)   (Show Source): You can put this solution on YOUR website!A rectangle is 10 cm longer than it is wide. A line segment cuts the area enclosed into two pieces, one of which is a square. The area of the rectangle is 118cm squared more than the area of the square. What is the width of the rectangle? : Let x = the width of the rectangle; (x+10) = the length : The square sides would = x, it's area would be x^2 : "The area of the rectangle is 118 cm squared more than the area of the square." Means the Area of the rectangle = (x^2 + 118) : We also know that the Area of the rectangle = x(x+10)= (x^2 + 10x) : Therefore: x^2 + 10x = x^2 + 118 x^2 - x^2 + 10x = 118 10x = 118 x = 11.8 cm is the width : : Check: 11.8^2 + 118 = 257.24 11.8 * 21.8 = 257.24 sq cm