# SOLUTION: construct a paralellogram ABCD in which BC=5.5cm, CD=2.5cm and angle ABC=60 degrees. Measure AC and BD

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 Question 57824: construct a paralellogram ABCD in which BC=5.5cm, CD=2.5cm and angle ABC=60 degrees. Measure AC and BDAnswer by venugopalramana(3286)   (Show Source): You can put this solution on YOUR website!construct a paralellogram ABCD in which BC=5.5cm, CD=2.5cm and angle ABC=60 degrees. Measure AC and BD IN A PARALELOGRAM OPPOSITE SIDES ARE EQUAL. HENCE AB=CD=2.5....BC=DA=5.5 DRAW BC = 5.5. WITH B AS CENTRE DRAW AN ARC OF RADIUS = AB = 2.5. AT B DRAW A LINE BX MAKING ANGLE OF 60 DEGREES WITH BC..THAT IS ANGLE XBC=60 LET THE ARC CUT BX AT A. WITH A AS CENTRE AND RADIUS EQUAL TO AD=5.5 DRAW AN ARC. WITH C AS CENTRE AND RADIUS EQUAL TO CD=2.5 DRAW AN ARC. LET THE 2 ARCS CUT AT D. JOIN CD AND DA ABCD IS THE REQUIRED PARALLELOGRAM. AC^2=AB^2+BC^2-2*AB*BC*COS(60) = 22.75 AC=4.77=4.8 BD=AC^2+CB^2-2*AC*CB*COS(120)= 50.25 BD=7.09=7.1