Lesson A shortcut to adding and subtracting fractions

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This Lesson (A shortcut to adding and subtracting fractions) was created by by jgr45(22) About Me : View Source, Show
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Contrary to popular belief, there is a fast way to add and subtract fractions with unlike denominators, and it does not involve finding a common denominator. It uses the following formulas, provided that no denominator is ever zero:
a%2Fb + c%2Fd = %28ad+%2B+bc%29%2Fbd
and
a%2Fb - c%2Fd = %28ad+-+bc%29%2Fbd
The steps are as follows:
1) Take the cross products and add/subtract them
2) Put the resulting sum or difference over the product of the denominators
3) Reduce if possible.
Some examples:
2%2F5 + 3%2F8
First, take the cross products. 2x8=16 and 5x3=15. Add 16 and 15 to get 31. This is your numerator. To get the denominator, multiply 5 and 8 to get 40, giving you 31%2F40, which is the exact same answer you would get with common denominators.

Now let's try a subtraction problem:
2%2F3 - 3%2F5
Again, take the cross products...2x5=10 and 3x3=9. Subtract 10 minus 9 to get 1. This is the numerator, To get the denominator, multiply the original denominators, 3 and 5, to get 15. So the answer to this one is 1%2F15.
Also, if you have numerators of 1, that makes the problem even easier because you're multiplying by 1 in your cross-products. In that case your answer would simply be the sum/difference of the denominators over the product of the denominators. For example, 1%2F4 + 1%2F3 = 7%2F12, and 1%2F3 - 1%2F7 = 4%2F21.

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