SOLUTION: Kindly help me. I don't have proper equation editor.
(x^2y^-3z)1/2 Divided by
x^1/2yz^-1/2
Thank you so much for the help.
Algebra.Com
Question 99690: Kindly help me. I don't have proper equation editor.
(x^2y^-3z)1/2 Divided by
x^1/2yz^-1/2
Thank you so much for the help.
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
[(x^2)(y ^-3)(z)]^1/2 / [(x^1/2) y z^-1/2)]
= [x y^(-3/2) z^(1/2)] / [(x^1/2) y z^-1/2)]
= [x^(1/2) z]/[y^(5/2)]
= z[xy^5]^(1/2)
================
Cheers,
Stan H.
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