SOLUTION: At a garage sale all books were one price, and all magazines were another price. Harriet bought 4 books and 3 magazines for $1.45, and June bought 2 books and 5 magazines for $1.2
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Question 93721: At a garage sale all books were one price, and all magazines were another price. Harriet bought 4 books and 3 magazines for $1.45, and June bought 2 books and 5 magazines for $1.25. What was the price of a book and what was the price of a magazine?
Please help me. I am having trouble understanding. Thank you.
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Harriet bought 4 books and 3 magazines for $1.45, and June bought 2 books and 5 magazines for $1.25. What was the price of a book and what was the price of a magazine?
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Let the price of a book be "b"; Let the price of a magazine be "m".
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EQUATIONS:
1st: 4b+3m=1.45
2nd: 2b+5m=1.25
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Multiply the 2nd equation by 2 to get:
3rd: 4b+10m=2.50
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Subtract the 1st equation from the 3rd to get:
4th: 7m=1.05
m = 0.15 (price of a magazine)
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Substitute that into the 2nd equation to solve for "b":
2b + 5*0.15 = 1.25
2b + 0.75 = 1.25
2b = 0.50
b = 0.25 (price of a book)
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Cheers,
Stan H.
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