SOLUTION: 1 over(x+h)^2 minus 1 over x^2 all this over h. I have the solutions manual but I don't now how they got x^2-(x+h)^2 for the numerator after mult. by LCD. What happened to the 1
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Question 84324This question is from textbook Coll. Alg. Graphing Approach
: 1 over(x+h)^2 minus 1 over x^2 all this over h. I have the solutions manual but I don't now how they got x^2-(x+h)^2 for the numerator after mult. by LCD. What happened to the 1's in the original numerator? Thank you! Jackie
This question is from textbook Coll. Alg. Graphing Approach
Answer by rapaljer(4671) (Show Source): You can put this solution on YOUR website!
It may help to write this in a different format:
DIVIDED BY
Now, you have to get the common denominator before you can subtract the first two fractions:
It's hairy, but this is why your numerator is , over the common denominator (times h, of course).
R^2 at SCC
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