SOLUTION: Hi how do I solve? 1-(1/8 � 2/4)2^ <----(squared) Thanks, Matt

Question 784703: Hi how do I solve?
1-(1/8 � 2/4)2^ <----(squared)
Thanks,
Matt
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
1-(1/8 � 2/4)2
---------------
= 1 - [(4-16)/32]^2
--------
= 1 - [-12/32]^2
--------
= 1 - (-3/8)^2
--------
= 1 -(9/64)
--------
= 55/64
--------------
Cheers,
Stan H.
----------------
RELATED QUESTIONS
How do I solve 4(1/4x - 2) = 0?... (answered by Alan3354)

how do i solve 64(3/16+5/8-1/4+1/2) thanks for ur... (answered by mananth)

how do you solve x2-3x+2? 8x(Squared)-4x=24? 2x(squared)+9x+4? 16x(squared)-8x=-1 (answered by checkley77)

Simplify: -5*(2*x-1)=3*(x+4) Thanks so much,... (answered by darq)

How Do You Factor 12z squared-16z-35. How Do You Solve... (answered by solver91311)

Hi, How do you sum a series like this; 1/1, 1/2, 1/3, 1/4, etc. Thanks... (answered by rfer)

How do I solve 4 1/8 + 7 1/2 + 6... (answered by Alan3354)

How do I solve and what are the answers please? (1) x - 2/4x - x + 2/3x= 1/6x + 2/3 (answered by Alan3354)

Using order of operations how do i solve... (answered by Casandra)